2x^2-2/x/2(x^2+12)/4x^2-29x

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Solution for 2x^2-2/x/2(x^2+12)/4x^2-29x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x^2-(x^2*((((2/x)/2)*(x^2+12))/4))-(29*x) = 0

(-1/4)*x*(x^2+12)+2*x^2-29*x = 0

2*x^2-1/4*x*(x^2+12)-29*x = 0

2*x^2-1/4*x*(x^2+12)-29*x = 0

2*x^2-1/4*x^3-3*x-29*x = 0

2*x^2-1/4*x^3-32*x = 0

2*x^2-1/4*x^3-32*x = 0

x*(2*x-1/4*x^2-32) = 0

2*x-1/4*x^2-32 = 0

DELTA = 2^2-(-32*(-1/4)*4)

DELTA = -28

DELTA < 0

x = 0

x = 0

x = 0

x in { 0} 

x belongs to the empty set

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